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If α and β are the zeros of the polynomial fx= 6x2+x 2, find ... - Byju

Web7 aug. 2015 · M y S o l u t i o n :: Given α and β are two roots of x 2 − p x + q = 0 So α + β = p and α ⋅ β = q Now α 3 + β 3 = ( α + β) 3 − 3 α ⋅ β ( α + β) = p 3 − 3 p q and α 2 + β 2 = … Webx − α = a (y − β)2 . Identifique o seu vértice, a equação do seu eixo de simetria e descreva a concavidade em função do sinal de a (onde a 6= 0). No caso de uma circunferência, … WebSolution Since α and β are the zeroes of the quadratic polynomial f(x)= 6x2+x−2, Sum of the zeroes = (α+β)= −b a = −1 6 The product of the zeroes =-2/6=−1/3 αβ= c a= −2 6 = … don\u0027t ask again for 60 days not working